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12n^2-26n=30
We move all terms to the left:
12n^2-26n-(30)=0
a = 12; b = -26; c = -30;
Δ = b2-4ac
Δ = -262-4·12·(-30)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2116}=46$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-46}{2*12}=\frac{-20}{24} =-5/6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+46}{2*12}=\frac{72}{24} =3 $
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